Question

The ages of Sheemaz and Sohaib are in the ratio of 5:7 . Four years later, the sum of their ages will be 56 years. What are their present ages ?​

Answer 1

Answer:

present ages are sheemaz is 20 years old and sohaib is 28

Step-by-step explanation:

lets take their ages as 5 x and 7 x respectively(according to the ratio given)

after 4 years their ages will be 5 x +4 and 7 x +4

it is said that the sum of their ages after 4 years is 56

this implies that 5 x+ 4+7 x + 4 = 56

adding the like terms ,we get 12 x +8 is =56

transposing 8 to the other side , we get

12 x =56-8

12 x = 48

x= 48 divided by 12

x= 4

therefore their present ages are

Sheemaz- 5x=5 times 4 =20

Sohaib- 7x = 7 times 4 = 28