Question

find the value of x such that PQ is equal to give the coordinates of p, 6, - 11, 3 and 8 respectively​

Answer 1

Answer:

PQ = QR

PQ2 = QR2

By distance formula,

(x - 2)2 + (-3 - 5)2 = (7 - x)2 + (9 + 3)2

x2 - 4x + 4 + 64 = 49 + x2 - 14x + 144

10x = 193 - 68 = 125

x = 12.5