The altitude from vertex P, in ∆PQR
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Step-by-step explanation:
From the figure, we have QR=QT+TR.
To find : QT and TR.
In the right angled triangle PTQ,
∠PTQ=90
o
[PT is attitude]
By Pythagoras Theorem, PQ
2
=PT
2
+QT
2
∴PQ
2
−PT
2
=QT
2
∴QT
2
=25
2
−15
2
=625−225=400 ...(1)
Similarly, in the right angled triangle PTR,
by Pythagoras Theorem, PR
2
=PT
2
+TR
2
∴TR
2
=PR
2
−PT
2
=172−15 2
=289−225=64
TR= 64
=8cm ...(2)
From (1) and (2)
QR = QT + TR = 20 + 8 = 28 cm
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PQ is your answer hope you like it
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