The altitudes AD and PS of two similar triangles ABC and PQR are 12 cm and 18 cm. Find the ratio of the areas of two triangles.
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We are given with the altitudes of Triangles ABC and PQR are:
AD=12cm ; PS=18cm.
Since we know that the ratio of two similar triangles is equal to the squares of corresponding altitudes.
ar(ABC)/ar(PQR)= AD. AD/PS.PS
= 12*12/18*18
= 4:9 Ans.
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