Question

The AM of 1,3,5, ....,(2n-1) is
(A)n+1
(C)n²
(B)n + 2
(D)n​

Answer 1

Answer:

I think b. is the correct answer

I hope it's helping you with me

then plz make me brainlist

Answer 2

Answer:

$n$

Step-by-step explanation:

$Given \: it \: \\ 1 \: 3 \: 5.........(2n - 1) \\ no.of \: terms \: = n \\ A.M. = \frac{total \: sum \: of \: terms}{no.of \: terms} \\ A.M = \frac{1 + 3 + 5 + 7..........(2n - 1)}{n} \\ A.M = \frac{ \frac{n}{2}(2 + (n - 1) \times 2) }{n} \\ a.m = \frac{ {n}^{2} }{n} \\ A.M = n \\ \\ \\ Hope \: it \: will \: help \: you..$