The amount of naoh required to be dissolved in one litre of solution to give a ph of 11 at 25°c
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pH=11
pOH = 3
So, [OH-] = 10-³
So, 10-³ = moles/volume
Since volume = 1 litre
Hence moles = 10-³
amount/molar mass = 10-³
Hence, amount = 10-³×molar mass
= 10-³ × 40
= 0.04 gms.
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