the angle of depression of a car standing on the ground from the top of a 66 m tower is 30° .find the distance of a car from the base of the tower
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Answer:
We know that
perpendicular/ base = tan theta
So
AB/BC = tan 30°
66/X = 1/√3
66√3 = x
114.31 is the answer
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Rahikhan:
hello
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given,
AB denotes the tower of length 66m and C denotes the position of car. hence, CBthe distance of the car and base of the tower. and angle c denotes the angle between car and top of the tower so angle c =30
we have to find the length CB.
in triangle ABC ,
tan c =perpendiculardivided by base
ta n 30 degree equals to ab by cb
TaN 30 degree is equals to 66 by cb
also by Trigonometric Table tan 30 =1by root. 3
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