The angle of elevation of a cloud from a point 200m above the lake is 30° and the angle of depression of its reflection in the lake is 60°.Find the height of the cloud above the lake
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in ADC,
tan 30•= H - 200/x
1/3 = H - 200 /x
x= √3(H -200)m
in ADF,
tan 60• = H+200/x
√3 = h + 200 /x
x = h +200/√3 ( -200)
on equating Both equation....
3(h-200) = h + 200
3h - h = 200 + 600
2h = 800
h= 400
so, required height
h = 400.
tan 30•= H - 200/x
1/3 = H - 200 /x
x= √3(H -200)m
in ADF,
tan 60• = H+200/x
√3 = h + 200 /x
x = h +200/√3 ( -200)
on equating Both equation....
3(h-200) = h + 200
3h - h = 200 + 600
2h = 800
h= 400
so, required height
h = 400.
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