the angle of elevation of an aeroplane from a point on the ground is 60 degree after a flight of 15 seconds the elevation changes to 30 degree and aeroplane is flying at a height of 3300√3m find the speed of the aeroplane
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In triangle ACE,
CE = 10800 m
AC = BD =
In triangle BED,
CD + DE = CE
CD + 3600 = 10800
CD = 10800 - 3600 = 7200 m
Distance travelled = 7200 m
Time taken = 30 seconds
In 1 second = 240 m
In 3600 seconds (1 hour) = 240 × 3600 = 864000 m = 864 km
In hour = 864 km
Speed = 864 km/h
PLEASE MARK AS BRAINLIEST
CE = 10800 m
AC = BD =
In triangle BED,
CD + DE = CE
CD + 3600 = 10800
CD = 10800 - 3600 = 7200 m
Distance travelled = 7200 m
Time taken = 30 seconds
In 1 second = 240 m
In 3600 seconds (1 hour) = 240 × 3600 = 864000 m = 864 km
In hour = 864 km
Speed = 864 km/h
PLEASE MARK AS BRAINLIEST
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