Question

The angle of elevation of the top of a tower from a point on the ground, which is
30 m away from the foot of the tower is 30°. The height of tower is​

Answer 1

Answer:

 let the height of the tower be x.

point away from tower=30m

angle of elevation=30°

so,        tan30° = x / 30

            1 / √3   = x / 30

            x   =    10√3 m

                 = 10 x 1.73

                 = 17.3 m

Answer 2

Step-by-step explanation:

In ∆ ABC,

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.