The angle subtended by a chord of a circle at its centre is 60 degree. ratio between chord and diameter of the circle is
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angle substended at the centre is 60degree
so ,it forms equilateral triangle
draw perpendicular from centre to the chord
then it will bisect the in two equal parts
let AB be the chord and OM be the perpendicular from cantre to the
chord so AM=2AB
then in triangle OAM
AM/radius =cos60
AM=R/2
AB=2AM=R
Then the ratio b/w chord and diameter=R/2R=1:2
so ,it forms equilateral triangle
draw perpendicular from centre to the chord
then it will bisect the in two equal parts
let AB be the chord and OM be the perpendicular from cantre to the
chord so AM=2AB
then in triangle OAM
AM/radius =cos60
AM=R/2
AB=2AM=R
Then the ratio b/w chord and diameter=R/2R=1:2
Answered by
1
Answer:
the answer should be 1:1
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