The angle which the vector Abar=3icap+6jcap+2kcap makes with the coordinate axes are
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A = 3 i + 6 j + 2 k
Magnitude of A is (3^2 + 6^2 + 2^2)^1/2 = 7
cos theta-x = 3/7 theta-x = 64.6 deg
cos theta-y = 6/7 theta-y = 31 deg
cos theta-z = 2/7 theta-z = 73.4 deg
These are known at the direction cosines of A
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