The angles of a triangle are in AP if the greatest angle equal to the sum of the other two then find the angles also find these angles are multiple of which angle
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let the first angle be 'x'
and common difference = d
Angles are
x , x + d , x + 2d
ATQ
x + ( x + d ) = x + 2d
2x + d = x + 2d
x = d
So the angles are
x , 2x , 3x
x + 2x + 3x = 180
(Angle sum property of triangle )
6x = 180
x = 30
So the angles are
30° , 60° , 90°
and common difference = d
Angles are
x , x + d , x + 2d
ATQ
x + ( x + d ) = x + 2d
2x + d = x + 2d
x = d
So the angles are
x , 2x , 3x
x + 2x + 3x = 180
(Angle sum property of triangle )
6x = 180
x = 30
So the angles are
30° , 60° , 90°
Charubrainly:
These angles are multiple of which angle
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