The angles of depression of the top and bottom of a pole standing on the same plane as the tower are observed to be 30* and 45* respectively. Find the height of the pole.
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Answered by
1
Answer:
ANSWER
Let AB is the tower of height 75 m and CD is the pole, such that ∠BDE=30
o
and ∠BCA=45
o
.
In △BAC,tan45
o
=
AC
AB
1=
AC
AB
AB=AC
AC=75 m
Now, DE=AC=75 m
In △BED,tan30
o
=
DE
BE
3
1
=
75
BE
BE=
3
75
BE=25
3
=43.3 m
Hence, the height of the pole =CD=AE=AB−BE=75−43.3=31.7 m
Answered by
1
Answer:
ANSWER
Let AB is the tower of height 75 m and CD is the pole, such that ∠BDE=30
o
and ∠BCA=45
o
.
In △BAC,tan45
o
=
AC
AB
1=
AC
AB
AB=AC
AC=75 m
Now, DE=AC=75 m
In △BED,tan30
o
=
DE
BE
3
1
=
75
BE
BE=
3
75
BE=25
3
=43.3 m
Hence, the height of the pole =CD=AE=AB−BE=75−43.3=31.7 m
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