Question

The angles of triangle are (x-40)°, ( x-20) °and ( 1/2x - 10) °. Find the value of .

Answer 1

we know ,
sum of all angles of any triangle is equal to 180° .

Here given,
first angle = ( x -40)°
second angle = (x -20)°
third angle = (x/2 - 10)°

first angle + second angle + third angle = 180°

( x -40)° + (x -20°) + (x/2 - 10)° = 180°

(x + x + x/2) -(40 + 20 + 10) = 180°

5x/2 = 250°

x = 100°

Answer 2

hope this will help you