Question

the angles quadrilateral are in AP whose common difference is 10 degree find the angles

Answer 1

$<b><I>HELLO !$

Sum of All the angles in QUADRILATERAL is 360

Let the First angle be X

$\red{\huge{Common Difference}}$

=10
we know that A/2[2x(N-1)d]

4/2[2x+(4-1)10]=360

2[2x+30]=360
2x+30=180
2x=180-30
2x=150
X=150/2
X=75

so,First is75,

second=75+10=85

Third=85+10=95

fourth=95+10=105
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