two equal side of triangle are each 5 Meters less than twice the third side. if the perimeter of the triangle of 55 Meters, find the lengths of its sides.
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Let, third side of triangle be x.
According to the question,
Two equal side of triangle are 5 meters less than the third side.
So, the two equal side = (2x - 5) meters
Given : perimeter of triangle = 55 meters
=> sum of all sides of triangle = 55
=> (2x-5) + (2x-5) + x = 55
=> 5x - 10 = 55
=> 5x = 55 + 10
=> x = 65/5
=> x = 13
Therefore,
Third side = x = 13 meters
other two equal sides = (2x - 5)
= (2×13 - 5) = 21 meters
According to the question,
Two equal side of triangle are 5 meters less than the third side.
So, the two equal side = (2x - 5) meters
Given : perimeter of triangle = 55 meters
=> sum of all sides of triangle = 55
=> (2x-5) + (2x-5) + x = 55
=> 5x - 10 = 55
=> 5x = 55 + 10
=> x = 65/5
=> x = 13
Therefore,
Third side = x = 13 meters
other two equal sides = (2x - 5)
= (2×13 - 5) = 21 meters
Answered by
0
Answer:
Let, third side of triangle be x.
According to the question,
Two equal side of triangle are 5 meters less than the third side.
So, the two equal side = (2x - 5) meters
Given : perimeter of triangle = 55 meters
=> sum of all sides of triangle = 55
=> (2x-5) + (2x-5) + x = 55
=> 5x - 10 = 55
=> 5x = 55 + 10
=> x = 65/5
=> x = 13
Therefore,
Third side = x = 13 meters
other two equal sides = (2x - 5)
= (2×13 - 5) = 21 meters
Step-by-step explanation:
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