The angular momentum of a body is 31.4 Js and its rate of revolution is 10 cycles per second. Calculate the moment of inertia of the body about the axis of rotation
Answers
Answered by
90
Data:
Angular Momentum = L = 31.4 Js
Angular frequency = ν = 10 rps
Moment of inertia = I = ?
Solution:
As,
ω = 2 π v
Substituting the values, we get:
ω = 2 x 3.14 x 10
ω = 62.8 rad/sec
Now,
L = I ω
I = L / ω
Again substituting the values, we get:
I = 31.4 / 62.8
I = 0.5 kg m²
which is the required answer.
Hopefully it helps. Thanks.
Angular Momentum = L = 31.4 Js
Angular frequency = ν = 10 rps
Moment of inertia = I = ?
Solution:
As,
ω = 2 π v
Substituting the values, we get:
ω = 2 x 3.14 x 10
ω = 62.8 rad/sec
Now,
L = I ω
I = L / ω
Again substituting the values, we get:
I = 31.4 / 62.8
I = 0.5 kg m²
which is the required answer.
Hopefully it helps. Thanks.
Answered by
1
Answer:
0.5 kg/m^2
Explanation:
answer is attached below
Hope it helps
Attachments:
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