Question

The area of a quadrilateral ABCD when length of the diagonal AC = 10 cm and length of perpendicular 13 m and DN from B and D on AC be 5cm and 6cm respectively is ​

Answer 1

Answer:

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Step-by-step explanation:

Given : Length of the diagonal (AC)=10 cm

Area of quadrilateral ABCD=ar(△ABC)+ar(△ACD)

= (1/2 × AC × BM) + (1/2 × AC × DL)

= 1/2 × AC (BM + DL)

= 1/2 × 10 (5 + 6)

= 5 × 11 cm²

= 55 cm²

Answer 2

Answer:

$answer$

BN = 5cm

DM =. 6cm

area of quadrilateral ABCD = area of triangle ACD

+ area of triangle ABC

$= \frac{1}{2} \times ac \times dm + \frac{1}{2} \times bn \times ac$

$= \frac{1}{2} \times 10 \times 6 + \frac{1}{2} \times 5 \times 10$

$= \frac{1}{2} (60 + 50)$

$= \frac{1}{2} \times 110$

$= {55cm}^{2}$

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