Question

The area of a rectangle is 20m^3 its length is 8 M
find the breadth and the perimeter of the rectangle​

Answer 1

Answer:

To find the area, we must first find out the measurements of the rectangle’s length and breadth (as Area = Length * Breadth)

l = length

b = breadth

We know the length is twice the breadth, therefore l = 2b

We also know that the perimeter p = 60m and can also be expressed as a sum of its sides where p = l + l + b + b = 60 which simplified is:

60 = 2l + 2b

Now we have 2 variables, but thankfully we were given a ratio (l = 2b) relating the two. Substituting 2b in for l gives us:

60 = 2(2b) + 2b = 4b + 2b = 6b

60 = 6b

b = 10 m

Now that we know the breadth we can find the length:

l = 2b → l = 2(10) = 20 → l = 20 m

With a breadth of 10 m and a length of 20 m, we can now find the area which is found by Area = Length * Breadth:

A = l*b = 20m * 10m = 200m^2 → A = 200 m^2

Answer 2

Given:-

• $\sf{Area \: of \: rectangle= {20m}^{3} }$
• $\sf{Length = 8m}$

To Find:-

• $\sf{Breadth =?}$
• $\sf{Perimeter \: of \: rectangle=?}$

Formula used:-

$\sf{\underline{\pink{Area \: of \: rectangle= l×b}}}$

$\red\dashrightarrow\sf{20 = 8 \times b}$

$\red\dashrightarrow\sf{ \frac{20}{8} = b}$

$\red\dashrightarrow\sf{b =\fbox\purple{ 2.5}}$

Now, we have to find perimeter of rectangle.

Formula used:-

$\sf{\underline{\purple{Perimeter\: of\: rectangle\: = 2×(l+b</u><u>)</u><u>}}}$

$\red\dashrightarrow\sf{perimeter = 2 \times (8 + 2.5)}$

$\red\dashrightarrow\sf{perimeter = 2 \times 10.5}$

$\red\dashrightarrow\sf{perimeter \: = \fbox\purple{21}}$

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HOPE IT HELPS!!