Question

the area of a rectangle is 630 sq. cm. if its length is 35cm. find the perimeter of rectangle​

Answer 1

$\sf Given \begin{cases} & \sf{Area\;of\;rectangle = \bf{630\;sq.\;cm}} \\ & \sf{Length\;of\;rectangle = \bf{35\;cm }} \end{cases}$

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Need to find: Perimeter of the Rectangle?

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☯ Let Breadth of Rectangle be x cm.

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$\dag\;{\underline{\frak{We\;know\;that,}}}$

$\star\;{\boxed{\sf{\purple{Area_{\;(rectangle)} = Length \times Breadth}}}}$

$:\implies\sf 35 \times x = 630$

$:\implies\sf x = \cancel{ \dfrac{630}{35}}$

$:\implies{\boxed{\sf{\pink{x = 18\;cm}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Thus,\;Breadth\;of\;rectangle\;is\; \bf{18\;cm}.}}}$

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Now, Finding area of rectangle,

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$\star\;{\boxed{\sf{\purple{Perimeter_{\;(rectangle)} = 2(Length + Breadth)}}}}$

Now, We have,

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Length of Rectangle, l = 35 cm

Breadth of Rectangle, b = 18 cm

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$:\implies\sf Perimeter_{\;(rectangle)} = 2(35 + 18)$

$:\implies\sf Perimeter_{\;(rectangle)} = 2 \times 53$

$:\implies{\boxed{\sf{\pink{Perimeter= 106\;cm}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Hence,\;The\; Perimeter\;of\;rectangle\;is\; \bf{106\;cm}.}}}$

Answer 2

Given:-

$\bigstar$The area of a rectangle is 630² cm

$\bigstar$The length of the rectangle is 35 cm

To Prove:-

$\bigstar$The perimeter of rectangle ?.....

Solution:-

$\bigstar$Using formula,

$\longrightarrow{ \boxed{ \boxed{ \boxed{ \bold{area \: of \: rectangle = length \times breadth}}}}}$

$\bigstar$To Find breadth,

$\\ \longrightarrow\sf \: 630 = 35b$

$\\ \longrightarrow \sf \: b = \frac{630}{35} = 18 \: cm$

$\longrightarrow{ \boxed{ \boxed{ \boxed{ \bold{b \: = 18 \: cm}}}}}$

$\bigstar$Using Formula,

$\longrightarrow{ \boxed{ \boxed{ \boxed{ \bold{perimeter = 2(l + b)}}}}}$

$\longrightarrow \sf \: = 2 \: (35 + 18) \\ \\ \longrightarrow \sf \: = 2 \: \times \: 53 \\ \\ \longrightarrow \sf \: = 106 \: cm$

$\longrightarrow{ \boxed{ \boxed{ \boxed{ \bold{perimeter\: = 106 \: cm}}}}}$

$\bigstar$Hence, the perimeter of rectangle is 106 cm