Question

The area of a rectangular piece of cardboard is 36 sq.cm and

its length is 9cm. What is the width of the cardboard? (2)​

Answer 1

Answer:

324 will be the answer!!!!!

Answer 2

Answer:

$\red\bigstar$ Width of the cardboard = 4cm.

SOLUTION

Area of the rectangular piece of cardboard = 36cm².

Length of the rectangular piece of cardboard = 9cm.

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 9 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large b cm}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}$

Area of a rectangle = l × b , Where l is the length and b is the breadth of the rectangle.

Here,

l = 9cm

Area = 36cm²

$\implies$ 36 = 9 × b

$\implies$ 36 = 9b

$\implies \sf b = \dfrac{36}{9}$

$\implies$ b = 4cm.

∴ The breadth of the cardboard = 4cm.

           The Cardboard          

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 9 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 4 cm}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}$

QUESTION FOR PRACTICE

The breadth of a rectangular field is 12m , if the are of the field is 336m² , find the length of the field?

Answer (For Verification) → Length of the field = 28m.