Question

the area of a rhombus is 200 sq.cm and length of one of its diagonals are is 10 cm . find the length of the other diagonal​

Answer 1

AREA of RHOMBUS formula : 1/2 * d1 * d2

where d1 and d2 are the diagnols of the rhombus.

200 = 1/2 * 10* d2

200*2 = 10*d2 (take 1/2 to the other side as it is in multiplication it becomes division)

400 = 10*d2

400/10 = d2 (take 10 to the other side as it is in multiplication it becomes division)

40 = d2

therefore the other diagnol is 40 cm

Answer 2

Step-by-step explanation:

$\mathbf\red{Given:-}$

• Area of rhombus = 200${cm}^{2}$
• Length of diagonal = 10cm

$\mathbf\blue{To\:Find:-}$

• The length of the other diagonal

$\mathbf\green{Solution:-}$

Area = 200 ${cm}^{2}$

Length of one of the diagonal $d_{1}$ = 10cm

Length of other diagonal $d_{2}$= ?

Area of rhombus =$\frac{1}{2} \times d_{1} \times d_{2}$

Given, Area = 200 ${cm}^{2}$

$\implies \frac{1}{2} \times d_{1} \times d_{2} = 200$

$\implies \frac{1}{2} \times 10 \times d_{2} = 200$

$\implies 5 \times d_{2} = 200$

$\implies d_{2} = \frac{200}{5}$

$\implies d_{2} = 40\: cm$

$\tt\purple{Therefore,\:The \: length\:of\: other\: diagonal\: is \: 40cm}$

$\large\orange{\underline{{\boxed{\textbf{Be\:Brainly}}}}}$