The area of a rhombus is equal to the area of a triangle. If base of Δ is 24 cm, its corresponding altitude is 16
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PLZ MARK MY SOLUTION AS THE BRAINLIEST.
BASE OF THE TRIANGLE = 24 cm
ALTITUDE OF THE TRIANGLE = 16 cm.
AREA OF THE TRIANGLE = 1/2 × BASE × HEIGHT
= 1/2 × 24 × 16 cm^2
= 12 × 16 cm ^2
= 192 cm^2
NOW, SINCE THE AREA OF THE TRIANGLE IS EQUAL TO THE AREA OF THE RHOMBUS.
SO, THE AREA OF THE RHOMBUS IS 192 cm^2.
BASE OF THE TRIANGLE = 24 cm
ALTITUDE OF THE TRIANGLE = 16 cm.
AREA OF THE TRIANGLE = 1/2 × BASE × HEIGHT
= 1/2 × 24 × 16 cm^2
= 12 × 16 cm ^2
= 192 cm^2
NOW, SINCE THE AREA OF THE TRIANGLE IS EQUAL TO THE AREA OF THE RHOMBUS.
SO, THE AREA OF THE RHOMBUS IS 192 cm^2.
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