Math, asked by isharmaakha, 1 year ago

The area of a square field is 1476225 m square .a motorist travels along it'd boundary at 36 km/he.in how much time will he return to the starting point?

Answers

Answered by capt0nemo
24
Area= (side)^2
side=√(1476225)

side=1215 metre
total 4 sides= 4×1215
= 4860 m

speed =36 km/hr
=36×(5/18)
=10 m/s
speed = (distance/time)
Time required to return to the starting point is,

time = 4860/10
= 486 seconds
Answered by stalwartajk
1

Answer: The motorist will take 8 minutes and 10 seconds to rreturn to the starting point .

Step-by-step explanation:

The area of a square field = 1476225 m square

a² = 1476225

a = 1215

Perimeter of the square field = 4a = 4×1215 = 4860 meters

Speed of the motorist = 36km/hrs.

Speed = 36×(5/18) = 10m/sec

So, we have to find how much time will he return to the starting point-

Speed = distance/time

time = distance/time

time = 4860/10 = 486 seconds

= 8 minutes and 10 seconds

Therefore the motorist takes 8 minutes 10 seconds to reach the starting point.

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