Math, asked by saqibaltaf123, 1 year ago

the area of a square field is 60025 metre. a man cycles along its boundary at 18 km/h. in how much time will he return to starting point?

Answers

Answered by wifilethbridge
523

Answer:

He will return to starting point in 196 seconds.

Step-by-step explanation:

Area of square field = 60025  sq.m.

Area of square = Side ^2

So,  60025=Side ^2

\sqrt{60025}=Side

245=Side

Since we are given that he cycles along the boundary of field

So, Perimeter of square field =4 \times Side

Perimeter of square field =4 \times 245

Perimeter of square field =980 m

So, Total distance = 980 m

Speed = 18 km/h =18 \times \frac{5}{18} =5 m/s

Time =\frac{Distance}{Speed}

Time =\frac{980}{5}

Time =196

Hence he will return to starting point in 196 seconds.

Answered by mithudeep2481
59

Answer:

He will return to starting point in 196 seconds.

Step-by-step explanation:

Area of square field = 60025  sq.m.

Area of square =

So,  

Since we are given that he cycles along the boundary of field

So, Perimeter of square field =

Perimeter of square field =

Perimeter of square field =

So, Total distance = 980 m

Speed = 18 km/h =

Hence he will return to starting point in 196 seconds.

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