The area of a square is 49sq cm A rectangle has the same perimeter as the square.if the length of the rectangle is 9.3cm what is its breadth?Also find which has greater area?
shivam7486:
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Solutions :-
Given :
Area of square = 49 cm²
Length of Rectangle = 9.3 cm
Find the side of square :-
Side = √Area
= √49 cm²
= 7 cm
Find the perimeter of square :-
Perimeter = 4 × side
= 4 × 7 cm
= 28 cm
Now,
Find the length of rectangle :-
We know,
Perimeter of Square = Perimeter of rectangle
Perimeter of rectangle = 2(Length + Breadth)
=> 28 = 2(9.3 + Breadth)
=> 28/2 = 9.3 + Breadth
=> 14 - 9.3 = Breadth = 4.7 cm
Find the area of rectangle :-
Area = Length × Breadth
= (9.3 × 4.7) cm²
= 43.71 cm²
Find which has greater area :-
Area of square = 49 cm²
Area of rectangle = 43.71 cm²
49 cm² > 43.71 cm²
Hence,
Breadth of rectangle = 4.7 cm
Area of square is greater than Area of rectangle.
_______________________
✯ @shivamsinghamrajput ✯
Given :
Area of square = 49 cm²
Length of Rectangle = 9.3 cm
Find the side of square :-
Side = √Area
= √49 cm²
= 7 cm
Find the perimeter of square :-
Perimeter = 4 × side
= 4 × 7 cm
= 28 cm
Now,
Find the length of rectangle :-
We know,
Perimeter of Square = Perimeter of rectangle
Perimeter of rectangle = 2(Length + Breadth)
=> 28 = 2(9.3 + Breadth)
=> 28/2 = 9.3 + Breadth
=> 14 - 9.3 = Breadth = 4.7 cm
Find the area of rectangle :-
Area = Length × Breadth
= (9.3 × 4.7) cm²
= 43.71 cm²
Find which has greater area :-
Area of square = 49 cm²
Area of rectangle = 43.71 cm²
49 cm² > 43.71 cm²
Hence,
Breadth of rectangle = 4.7 cm
Area of square is greater than Area of rectangle.
_______________________
✯ @shivamsinghamrajput ✯
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