Question

the area of a trapezium is 34 CM square and the length of one of the parallel side is 10 cm and its height is 4 cm find the length of the other parallel side​

Answer 1

Given :

• Area of trapezium = 34 cm²

• Length of one parallel side = 10 cm

• Height = 4 cm

To Find :

• Length of the other parallel side

Solution :

Let the parallel sides of trapezium be a and b. We know the value of a is 10 cm, we've to find the value of b

We know that,

$\bigstar\: \: \sf \: Area_{trapezium} = \dfrac{1}{2} (a + b) \times h$

$\longrightarrow \sf \: 34 = \dfrac{1}{2} (10 + b) \times 4$

$\longrightarrow \sf \: 34 =(10 + b)2$

$\longrightarrow \sf \: 34 = 20 + 2b$

$\longrightarrow \sf \: 34 - 20 = 2b$

$\longrightarrow \sf \: 2b = 14$

$\longrightarrow \sf \: b = \dfrac{14}{2 }$

$\longrightarrow \sf \: b = 7 \: cm$

$\therefore$ Length of other parallel side is 7 cm.

Answer 2

Question:-

➣ The area of a trapezium is 34 cm² and the length of one of the parallel side is 10 cm and its height is 4 cm. Find the length of the other parallel side.

➣AnSwEr:-

➣ Given :

• Area of trapezium = 34 cm²

• Length of one parallel side = 10 cm

• Height = 4 cm

➣ Find :

• Length of the other parallel side:-

➣ Method:-

Let the parallel sides of trapezium be x and y. The value of x is 10 cm, value of y = ?

➣

Area of Trapezium =${\bf{\dfrac{1}{2} (x + y) \times h}}$

=} 34 =${\dfrac{1}{2} (10 + y) \times 4}$

=} 34 =(10 + y) × 2

=} 34 = 20 + 2y

=} 34 - 20 = 2y

=} 2y = 14

=} y =$\dfrac{14}{2 }$

=} y =$\cancel{\dfrac{14}{2}}$

=} $\large{y=}$$\red{7cm}$

➣Length of other parallel side is:

$\huge{\purple{7cm}}$