the area of a trapezium is 90cm ² . If one parallel line is 6 cm longer than the other and the distance between them is 6 cm , find the lengths of the parallel sides.
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Answer:
12cm and 18cm
Step-by-step explanation:
given :-
area of trapezium= 90cm²
distance between parallel lines( height) = 6cm
one line is 6cm more than other.
Let the smaller line be 'x'
then,
longer line will be= x+6
we know that,
area of trapezium= 1/2*(sum of parallel side)* height
90cm²= [1/2*{x+x+6}*6]
90= 1/2 * 2x+6 * 6
90/6*2= 2x+6
30= 2x+6
30-6= 2x
24=2x
x= 24/2
x=12
hence, first side(smaller) =x=12cm
second side(larger)=x+6=18cm
now, we can say,
the sides are 12cm and 18cm
( please make rate my solution)
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