Question

the area of a triangle whose sides are 15cm 16cm and 17cm

Answer 1

$s = \frac{a + b + c}{2} \\ \\ = > s = \frac{15 + 16 + 17}{2} = 24 \\ \\ \\ a = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ a = \sqrt{24(24 - 15)(24 - 16)(24 - 17)} \\ \\ = > a = \sqrt{24 \times 9 \times 8 \times 7} \\ \\ = > a = \sqrt{2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 2 \times 2 \times 2 \times 7} \\ \\ = > a = 2 \times 2 \times 2 \times 3 \sqrt{21} \\ \\ = > a = 24 \sqrt{21}$

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Answer 2

Answer:

s=

2

a+b+c

=>s=

2

15+16+17

=24

a=

s(s−a)(s−b)(s−c)

a=

24(24−15)(24−16)(24−17)

=>a=

24×9×8×7

=>a=

2×2×2×3×3×3×2×2×2×7

=>a=2×2×2×3

21

=>a=24

21