Question

The area of a triangle whose sides are 15m , 16m, 17m is :

Answer 1

ANSWER:-

Given:

In a triangle sides are;

•A= 15cm

•B= 16cm

•C= 17cm

To find:

Area of triangle.

Solution:

A/q

Using Heron's Formula:

$s = \frac{a + b + c}{2} \\ \\ = > \frac{15 + 16 + 17}{2} \\ \\ = > \frac{48}{2} \\ \\ = > 24m$

&

Area of triangle:

$A= \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = > \sqrt{24(24 - 15)(24 - 16)(24 - 17)} \\ \\ = > \sqrt{24(9)(8)(7)} \\ \\ = > \sqrt{12096} \\ \\ = > 109.98 {m}^{2}$

Thus,

The area of triangle is 109.98m²

Hope it helps ☺️

Answer 2

Step-by-step explanation:

three side are given then the area of triangle is find out by Heron's formula.......

s = semiperimeter of given sides

= 24

a,b,c =given side = 15,16,17

heron's formula =

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{24(24 - 15)(24 - 16)(24 - 17)}$

Therefore ,

= √8×3×9×8×7

= 24√21

therefore the area of triangle is

24√21 cm^2

THANK YOU