Question

the area of ΔABC is 18cm ^2 .If the height AD is 3cm,find the length of side BC.

Answer 1

$given \\ \\ area \: of \: triangle \: abc = 18cm {}^{2} \\ \\ \frac{1}{2} \times b \times 3 = 18 \\ \\ 3b = 36 \\ \\ b = 12 cm \\ \\ base \: of \: triangle \: abc = 12cm$

Answer 2

hey friend

here is your answer

given that area of ΔABC = 18cm²

we know that area of a triangle = 1/2 × b × h

h = 3cm

3 × BC = 18 × 2

BC = 36 / 3

BC = 12cm

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