Question

the area of an equilateral triangle is 4√3 cm its perimeter is​

Answer 1

SOLUTION:-

Given:

The area of an equilateral ∆ is 4√3cm.

So,

We know that, area of an equilateral ∆ is;

$= > \frac{ \sqrt{3} }{4} {a}^{2}$

Therefore,

$= > \frac{ \sqrt{3} }{4} {a}^{2} = 4 \sqrt{3} \\ \\ = > {a}^{2} = \frac{4 \sqrt{3} \times 4 }{ \sqrt{3} } \\ \\ = > {a}^{2} = 16 \\ \\ = > a = \sqrt{16} \\ \\ = > a = 4cm$

Now,

Perimeter of ∆ is = 3× side

=) 3 × 4cm

=) 12cm

Hope it helps ☺️

Answer 2

$\huge {\fcolorbox {red} {pink}{HOLA...!!}}$

$Area \:of \:equilateral \:triangle = \frac {\sqrt {3}{a}^{2}} {4}$

$= > 4 \sqrt{3} = \frac{ \sqrt{3} {a}^{2} }{4} \\ \\ = > 16 \sqrt{3} = \sqrt{3} {a}^{2} \\ \\ = > \frac{16 \sqrt{3} }{ \sqrt{3} } = {a}^{2} \\ \\ = > a = \sqrt{16} \\ \\ =>a = 4 \: cm$

$Perimeter \:of \:triangle = 3×a$

$= > 3 \times 4 \\ \\ = > 12 \: cm$

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$\large {\fcolorbox {red} {pink} {HOPE \:IT \:HELPS}}$