Question

The area of APQR with vertices P(1, -1). (1,0) and r(0, 1) (in square units) is​

Answer 1

Answer:

the area of a cube is 61110 and open this file

Answer 2

$Area= \frac{1}{2} [x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]</p><p>$

By substituting the values we get,

$= \frac{1}{2} [1(0−1)+1(1-(-1))+0(-1-0)]</p><p>$

$= \frac{1}{2} (1 \times - 1 + 1 \times 2 + 0) \\ = \frac{1}{2} ( - 1 + 2) \\ = \frac{1}{2} = 0.5 {m}^{2}$