Question

The area of cross section at the end X of a hydraulic jack is 0.005 m2 and that at Y is 0.1 m2. If a force of 10 N is applied at the end X, what is the force felt at Y ?

Captionless Image
500 N
3oo N
200 N
100 N​

Answer 1

Answer:

o.5 newton

Explanation:

f2=a2/a1×f1

f1=.005/.1×10

f1=o.5 newton

Answer 2

answer : 200 N

hope it is helpful

please mark me the brainliest