Question

The area of isosceles triangle whose equal sides are equal to 3 cm and other side is 4 cm.
Its area is
​

Answer 1

Step-by-step explanation:

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Answer 2

The area would be 2√5 cm.

Step-by-step explanation:

Since we have given that

a = 3 cm

b = 3 cm

c = 4 cm

so, semi perimeter would be

$s=\dfrac{a+b+c}{2}=\dfrac{3+3+4}{2}=\dfrac{10}{2}=5\ cm$

so, using "Heron's formula " we get that

$\sqrt{s(s-a)(s-b)(s-c)}\\\\=\sqrt{5(5-3)(5-3)(5-4)}\\\\=\sqrt{5\times 2\times 2\times 1}\\\\=2\sqrt{5}$

Hence, the area would be 2√5 cm.

# learn more:

The area of isosceles triangle whose equal sides are equal to 3 cm and other side is 4 cm.

Its area is​

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