Question

the area of rectangle 24cmsq and it's perimeter is 22m then it's sides in meter are

Answer 1

Area of rectangle = L X B = 24....(1)

Perimeter = 2[L + B] = 22....(2)

From (1) we have L = 24/B

Putting this in (2) we get

2[24/B + B] = 22

48/B + 2B = 22

48 + 2B^2 = 22B (Multiplied both sides by B)

B^2 - 11B + 24 = 0  (divided both sides by 2)

B^2 - 8B - 3B + 24 = 0

B(B - 8) - 3(B - 8) = 0

(B-8)(B-3) = 0

B = 8 or 3

As we know breadth < length so we take B = 3

So L = 24/3 = 8

Therefore sides of rectangle are 8 m and 3 m.