Question

The area of rectangle whose length is 5 units more than twice its width is 75 square

Answer 1

I guess we have to Find Length and breadth

So, let breadth be x

Length = 2x+5

So , area of Rectangle = Length×Breadth

or, x(2x+5) = 75

or, 2x²+5x = 75

or, 2x²+5x-75 = 0

or, 2x²+15x-10x-75=0

or, x(2x+15)-5(2x+15)=0

or, (x-5)(2x+15)

Therefore, one of the sides is 5units and other is 15units.
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