The area of rectangular field is 7200sq mtrs and its width is 80mtrs find its perimeter
Answers
Answered by
2
Solution.
Area of rectangle = Length* Breadth
=> length* 80= 7200
=> length = 90m
so, perimeter of rectangle= 2(Length+ breadth)
= 2 (80+90)
= 2* 170
= 340m
___________
☺
Area of rectangle = Length* Breadth
=> length* 80= 7200
=> length = 90m
so, perimeter of rectangle= 2(Length+ breadth)
= 2 (80+90)
= 2* 170
= 340m
___________
☺
Answered by
6
Hii...☺
Here is your answer....☺
==================================
Area of rectangular field = 7200m²
width = 80m
Now, area of rectangular field = length × Width
→ 7200m² = length ×80
→ length = 7200/80
→ length = 90m
Perimeter = 2(l+b)
→ 2 ( 90 + 80 )
→ 2( 170)
→ 340m
Hence, perimeter of the rectangular field = 340m
=================================
Hope this helps you...☺
Thanks...☺
Here is your answer....☺
==================================
Area of rectangular field = 7200m²
width = 80m
Now, area of rectangular field = length × Width
→ 7200m² = length ×80
→ length = 7200/80
→ length = 90m
Perimeter = 2(l+b)
→ 2 ( 90 + 80 )
→ 2( 170)
→ 340m
Hence, perimeter of the rectangular field = 340m
=================================
Hope this helps you...☺
Thanks...☺
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