Question

The area of rhombus is 144cm.sq One of its diagonals is twice the other Find the length of the shorter diagonal

Answer 1

let length of shorter diagnol be x
then other diagonal = 2x

Now,
area of rhombus = product of its diagonal
144 = 2x × x
144 = 2x^2
144/2= x^2
72= x^2

$x = \sqrt{72}$


$x = 6 \sqrt{2}$