the area of right triangular region is 12 9.5 CM square if one of the sides containing the right angle is 14.8 find the other one
Answers
Answer:
Let the base of triangle to be x and height is given 14.8cm.
Area of triangle=1/2*Base*height
129.5=1/2*x*14.8
therefore,x=129.5*2/14.8=17.5cm
Given :--
- Area of Right angled ∆ = 129.5cm²
- One side containing Right angle = 14.8cm.
- Find other side containing Right Angle ?
Formula used :---
→ it has been said that , the side containing Right angle is 14.8 cm , that Means , its Either Perpendicular or base of Right angled ∆ .
→ Area of Right angled ∆ = 1/2 * Base * Perpendicular .
______________________
Solution :---
Let side other than 14.8cm that containing is x cm.
Than,
→ 1/2 * 14.8 * x = 129.5
→ 7.4x = 129.5
Dividing both sides by 7.4 we get,
→ x = 17.5 cm
Hence, Length of other side containing Right angle is 17.5cm.
____________________________
** If we have to Find third side also that is Hypotenuse of ∆, than we will use Pythagoras Theoram **,
→ (Perpendicular)² + (Base)² = (Hypotenuse)²
→ (14.8)² + (17.5)² = H²
→ H² = (525.29)
→ H = 22.91 cm .
So, Third Side of ∆ will be 22.91 cm.