Question

the area of the sector with radius 45cm and the angle 30° is?? (in square cms) ​

Answer 1

Solution :

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The radius of the circle is 45 cm .

Angle of the sector is 30%

Area of the sector :

> [ Theta / 360 ] ° π r² .

> ( 30/360) π r² .

> 1/12 × π × 45 × 45

> 168.75 π cm² .

This is the required answer.

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Additional Information :

Area of a circle - π r² .

Perimeter of a circle : 2 π r

Perimeter of a sector : ( theta / 360) × 2πr

Area of the sector : [ Theta / 360 ] × π r² .

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Answer 2

Step-by-step explanation:

$\blue{ \underline{ \bf{QUESTION} : }}$

The area of the sector with radius 45cm and the angle 30° is?? (in square cms)

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$\boxed{ \huge{ \bold{Given}}}$

• Radius (r) = 45 cm

• $\sf{ Angle(\theta) = {30}^{ \degree}}$

$\boxed{ \bold{ \huge{ to \: find}}}$

• Area of the Sector

$\star{ \pink{ \underline{ \underline{Ｓｏｌｕｔｉｏｎ : - }}}}$

We Know that ➠

$\boxed{ \boxed{ \red{Area \: of \: Sector \: = \frac{ \theta}{ {360}^{ \degree}} \times \pi \times ( {r})^{2} }}}$

${ \implies{ \sf {Area \: of \: Sector = \frac{30 \degree}{360 \degree}} \times \frac{22}{7} \times {(45)}^{2}} }$

${ \implies{ \sf {Area \: of \: Sector = \frac{30 \degree}{360 \degree}} \times \frac{22}{7} \times {45 \times 45} }}$

${ \implies{ \sf {Area \: of \: Sector = \frac{11 \times 2025}{42}}}}$

${ \implies{ \sf {Area \: of \: Sector = {\boxed{ \red{ \frak 530.35 \: {cm}^{2} }}}}}}$

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