Question

The area of trapezium is 248sq.M and its height is 8m if one of the parallel side is smalller than the other by 4m find two parallel sides

Answer 1

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Answer 2

Answer:-

Given:-

The area of trapezium is 248m² and its height is 8m. It one of the parallel side is smaller than the other by 4m.

To find:'

The two sides of the trapezium.

The two sides of the trapezium.Explanation:

The two sides of the trapezium.Explanation:We have,

The two sides of the trapezium.Explanation:We have,Area of trapezium= 248m²

The two sides of the trapezium.Explanation:We have,Area of trapezium= 248m²Height of the trapezium= 8m

A/q

Let the length of one of the parallel side be R m

Let the length of one of the parallel side be R mLet the length of other parallel side be (R- 4)m

Let the length of one of the parallel side be R mLet the length of other parallel side be (R- 4)mWe know that formula of the area of trapezium:

$=\frac{1}{2} *(sum\:of\:base)*height= </u></p><p><u>[tex]=\frac{1}{2} *(sum\:of\:base)*height= 2</u></p><p><u>[tex]=\frac{1}{2} *(sum\:of\:base)*height= 21$

$∗(sumofbase)∗height$

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$begin{gathered}=\:\frac{1}{2} *(R+R-4)*8=248\\\\=\:\frac{1}{2} (2R-4)*8=248\\\\=\:1(2R-4)4=248\\\\=\:(2R-4)=\frac{248}{4} \\\\=\:2R-4= 62\\\\=\:2R=62+4\\\\=\:2R=66\\\\=\:R=\frac{66}{2} \\\\=\:R=33m\end{gathered} </u></p><p><u>[tex]begin{gathered}=\:\frac{1}{2} *(R+R-4)*8=248\\\\=\:\frac{1}{2} (2R-4)*8=248\\\\=\:1(2R-4)4=248\\\\=\:(2R-4)=\frac{248}{4} \\\\=\:2R-4= 62\\\\=\:2R=62+4\\\\=\:2R=66\\\\=\:R=\frac{66}{2} \\\\=\:R=33m\end{gathered} = </u></p><p><u>[tex]begin{gathered}=\:\frac{1}{2} *(R+R-4)*8=248\\\\=\:\frac{1}{2} (2R-4)*8=248\\\\=\:1(2R-4)4=248\\\\=\:(2R-4)=\frac{248}{4} \\\\=\:2R-4= 62\\\\=\:2R=62+4\\\\=\:2R=66\\\\=\:R=\frac{66}{2} \\\\=\:R=33m\end{gathered} = 2</u></p><p><u>[tex]begin{gathered}=\:\frac{1}{2} *(R+R-4)*8=248\\\\=\:\frac{1}{2} (2R-4)*8=248\\\\=\:1(2R-4)4=248\\\\=\:(2R-4)=\frac{248}{4} \\\\=\:2R-4= 62\\\\=\:2R=62+4\\\\=\:2R=66\\\\=\:R=\frac{66}{2} \\\\=\:R=33m\end{gathered} = 21$

∗(R+R−4)∗8=248

∗(R+R−4)∗8=248=

∗(R+R−4)∗8=248= 2

∗(R+R−4)∗8=248= 21

∗(R+R−4)∗8=248= 21

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)=

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R=

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 2

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 266

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 266

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 266

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 266 =R=33m

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 266 =R=33m

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 266 =R=33m

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 266 =R=33m Thus,

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 266 =R=33m Thus,The length of one of the parallel side,R= 33m

∗(R+R−4)∗8=248= 21 (2R−4)∗8=248=1(2R−4)4=248=(2R−4)= 4248 =2R−4=62=2R=62+4=2R=66=R= 266 =R=33m Thus,The length of one of the parallel side,R= 33mThe length of other of the parallel side, (33-4)m= 29m.