the area of trapezium is 39cmsq the distance between its parallel side is 6cm if one of the parallel side is 5 cm, then find the other side
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Area of trapezium=1/2×(sum of parallel sides)×height
39=1/2×(5+x)×6
39×2=30+6x
78=30+6x
78-30=6x
6x=48
x=8
39=1/2×(5+x)×6
39×2=30+6x
78=30+6x
78-30=6x
6x=48
x=8
saketsingh1994:
tq bhai
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area of trapezium =1/2( sum of parallel side)h
let other parallel side be x
39=1/2(5+x)6
39= 15+3x
39-15=3 x
24=3x
8= x
let other parallel side be x
39=1/2(5+x)6
39= 15+3x
39-15=3 x
24=3x
8= x
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