The area of triangle ,whose base and the corresponding altitude are 15cm and 7cm,is equals to a right triangle whose one of the side containing the right angle is 10.5cm.Find the other side of triangle.
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27
Answer is 10 cm
0.5× 15×7=0.5×x×10.5
So solving x = 10 cm
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Please Please mark It as brainliest answer
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I request u
0.5× 15×7=0.5×x×10.5
So solving x = 10 cm
Please mark it as brainliest answer
I request u
Please
Please Please mark It as brainliest answer
Please
I request u
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Given that Base of the right-angled triangle b = 15cm.
Given that Altitude of the right-angled triangle h = 7cm.
We know that Area of the triangle = 1/2 * b * h
= 105/2
= 52.5cm^2.
Given that Area of the one side of the triangle = 10.5cm.
Therefore the other side of the triangle = (2 * 52.5)/10.5
= 105/10.5
= 10cm.
Therefore the other side of the triangle = 10cm.
Hope this helps!
Given that Altitude of the right-angled triangle h = 7cm.
We know that Area of the triangle = 1/2 * b * h
= 105/2
= 52.5cm^2.
Given that Area of the one side of the triangle = 10.5cm.
Therefore the other side of the triangle = (2 * 52.5)/10.5
= 105/10.5
= 10cm.
Therefore the other side of the triangle = 10cm.
Hope this helps!
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