the area of two equal circles in the figure is 308 CM
square find the perimeter of the rectangle
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Answered by
194
Area of two equal circles is 2 x pi r²
=>2 x 22/7 x r x r=308
=>r²=308/2 x 7/22
=>r²=49
=>r=√49=7cm,,
Now,
2r = diameter of circle = length of rectangle
length=14 cm
radius of circle = breadth of rectangle=7 cm
∵Perimeter of rectangle = 2(l+b)
= 2(14+7)
= 2 x 21 = 42cm
∴The perimeter of the rectangle is 42 cm,,
=>2 x 22/7 x r x r=308
=>r²=308/2 x 7/22
=>r²=49
=>r=√49=7cm,,
Now,
2r = diameter of circle = length of rectangle
length=14 cm
radius of circle = breadth of rectangle=7 cm
∵Perimeter of rectangle = 2(l+b)
= 2(14+7)
= 2 x 21 = 42cm
∴The perimeter of the rectangle is 42 cm,,
Answered by
125
i hope this will help you
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