The area of two similar triangle ABC and PQR are 25cm² and 49cm² respectively and QR=9.8 cm,find BC=..............
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Step-by-step explanation:
By the theorem i.e ratio of area of 2 similar triangles is equal to the ratio of the squares of there coresponding sides
ar(ABC). ( BC)^2
-------------- = -----
are(PQR) (QR)^2
25/49 = (BC)^2/(9.8)^2
(BC)^2 = 25/49 x 96.04
(BC) = √49
BC. = 7
harsh7182:
how 9.6 to 9.8
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