The areas of two similar triangles are 121 cm² and 64 cm² respectively. If the median of the first triangle is 12.1 cm, find the corresponding median of the other.
Answers
Answered by
190
SOLUTION :
Given : Area of two similar triangles is 121cm² and 64 cm² .
Since, the ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding medians.
ar(∆1)/ar(∆2) = (median1/median2)²
121 / 64 = (12.1/median2)²
On taking square root on both sides,
√121 / 64 = √(12.1/median2)²
11/8 = 12.1 /median2
11× Median2 = 12.1 × 8
Median 2 = (12.1× 8)/11
Median2 = 1.1 × 8
Median2 = 8.8 cm
Hence, the corresponding median of the other is 8.8 cm.
HOPE THIS ANSWER WILL HELP YOU...
BrainlyPromoter:
nice answer sis
Answered by
61
Hello user
Since , we know that the medians of two similar triangles are proportional to the square root of the ratio of their areas
So,
Let the median of other triangle be x
(121/64)^1/2 = 12.1/x
11/8 = 12.1/x
x = 8 × 12.1 / 11
x = 1.1 × 8
x = 8.8 cm
So, the median of other triangle will be 8.8 cm.
Hope it works
Since , we know that the medians of two similar triangles are proportional to the square root of the ratio of their areas
So,
Let the median of other triangle be x
(121/64)^1/2 = 12.1/x
11/8 = 12.1/x
x = 8 × 12.1 / 11
x = 1.1 × 8
x = 8.8 cm
So, the median of other triangle will be 8.8 cm.
Hope it works
Similar questions