Question

the areas of two similar triangles are respectively 25 CM^2 square and 81 cm ^2 find the ratio of their corresponding sides

Answer 1

let , first triangle be ABC
and another one is PQR
so,.
ar(ABC)/ar(PQR)=25/81
so,AB^2/PQ^2=25/81
so,AB/PQ=5/9

Answer 2

Answer:

The ratio of corresponding sides of triangles are 5:9.

Step-by-step explanation:

It is given that the areas of two similar triangles are respectively 25 cm² square and 81 cm².

The area of two similar triangles and the square of their corresponding sides are proportional.

Let their corresponding sides are x and y respectively.

$\frac{A_1}{A_2}=\frac{x^2}{y^2}$

$\frac{25}{81}=(\frac{x}{y})^2$

Taking square root both the sides.

$\sqrt{\frac{25}{81}}=\frac{x}{y}$

$\frac{5}{9}=\frac{x}{y}$

Therefore the ratio of corresponding sides of triangles are 5:9.