The average age of 3 boys is 25 yrs and their ages in the proportion 3:5:7.find the age of the youngest boy.
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Let the age of three boys be b1, b2 and b3.
(b1 + b2 + b3)/3 = 25
b1 + b2 + b3 = 75 ...(1)
given b1 : b2 : b3 = 3 : 5 : 7
If b1 = 3k, then b2 = 5k and b3 = 7k
but from 1,
3k + 5k + 7k = 25
15k = 25
k = 5/3
therefore b1 = 5 years,
b2 = 25/3 years,
b3 = 35/3 years
(b1 + b2 + b3)/3 = 25
b1 + b2 + b3 = 75 ...(1)
given b1 : b2 : b3 = 3 : 5 : 7
If b1 = 3k, then b2 = 5k and b3 = 7k
but from 1,
3k + 5k + 7k = 25
15k = 25
k = 5/3
therefore b1 = 5 years,
b2 = 25/3 years,
b3 = 35/3 years
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